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The solution of $\large\frac{dx}{dy}+\frac{x}{y}$$=x^2$ is :

\[\begin {array} {1 1} (a)\;\frac{1}{y}=cx- x\log x & \quad (b)\;\frac{1}{x}=cy- y\log y \\ (c)\;\frac{1}{x}=cx + x\log y & \quad (d)\;\frac{1}{y}=cx-y \log x \end {array}\]

1 Answer

$(b)\;\frac{1}{x}=cy- y\log y$
answered Feb 27, 2014 by meena.p
 
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