**Toolbox:**

- A relation R in a set A is called $\mathbf{ reflexive},$ if $(a,a) \in R\;$ for every $\; a\in\;A$
- A relation R in a set A is called $\mathbf{symmetric}$, if $(a_1,a_2) \in R\;\Rightarrow\; (a_2,a_1)\in R \; for \;a_1,a_2 \in A$
- A relation R in a set A is called $\mathbf{transitive},$ if $(a_1,a_2) \in R$ and $(a_2,a_3) \in R \; \Rightarrow \;(a_1,a_3)\in R$ for all$\; a_1,a_2,a_3 \in A$

Given : m,n are integer z

Relation R defined by

m R n if m is a integral multiple of n

Let mRm m is integral multiple of m itself

Therefore R is reflexive

Let $m R n$

=> m is integral multiple of n

$=>m=pn\qquad where \;p \in Z$

$=> n=\frac{1}{p} m$

$\frac {1}{p} \notin z \;for \;all\;p \in z$

Therefore n is not integral mutiple of m

mRn does not imply n R m

R is not symmetric

Solution: Hence the given statment is 'False'