Q)
(chatquestion)...The total length of a sonometer wire fixed between two bridges is 10 cm.
Now two more bridges are placed to divide the length of the wire in the ratio
6:3:2.If the tension in the wire is 400 N and the mass per unit length of the
wire is 0.01 kg m', then the minimum common frequency with which all the
three parts can vibrate, is
(A*) 1000 HZ
(B) 1100 Hz
(C) 100 Hz
(D) 110 Hz
1 Answer
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