logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  EAMCET  >>  Physics
0 votes

The center of mass of three particles of masses 1 kg,2 kg and 3 kg is at (2,2,2). The position of the fourth mass of 4 kg to be placed in the system as that the new center of mass is at (0,0,0) is :

\[\begin {array} {1 1} (a)\;(-3,-3,-3) & \quad (b)\;(-3,3,-3) \\ (c)\;(2,3,-3) & \quad (d)\;(2,-2,3) \end {array}\]
Can you answer this question?
 
 

2 Answers

0 votes
(A) (-3,-3,-3)
Hence A is the correct answer.
answered Mar 24, 2014 by meena.p
 
0 votes
As the c.m. of three particles is at (2,2,2) ∴The total mass = 1+2+3 = 6kg Now consider the 4kg mass at the position (x,y,z) Now centre of mass of total system at (0,0,0) ∴ 624 0 10 × + x = ⇒ 12 = -4x ⇒ x = -3 Similarly 624 0 12 × + y = ⇒ y = -3 624 0 12 × + z = ⇒ z = -3 From the above we can conclude that x = -3, y = -3, z = -3
answered Sep 13 by ruttulahimana37
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...