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The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If the coefficient of friction between the body and the inclined plane is $\large\frac{1}{2 \sqrt 3},$ the angle of the inclined plane is :

\[\begin {array} {1 1} (a)\;60^{\circ} & \quad (b)\;45^{\circ} \\ (c)\;30^{\circ} & \quad (d)\;15^{\circ} \end {array}\]
Will u please tell  how to do that

1 Answer

$(C) 30^{\circ}$
Hence C is the correct answer.
answered Mar 24, 2014 by meena.p

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