Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If the coefficient of friction between the body and the inclined plane is $\large\frac{1}{2 \sqrt 3},$ the angle of the inclined plane is :

\[\begin {array} {1 1} (a)\;60^{\circ} & \quad (b)\;45^{\circ} \\ (c)\;30^{\circ} & \quad (d)\;15^{\circ} \end {array}\]
Can you answer this question?

1 Answer

0 votes
$(C) 30^{\circ}$
Hence C is the correct answer.
answered Mar 24, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App