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The ratio of specific heats of a gas is $ \gamma$. The change in internal energy of one mole of the gas, when the volume changes from V to 2V at constant pressure P is :

\[\begin {array} {1 1} (a)\;\frac{\gamma-1}{PV} & \quad (b)\;PV \\ (c)\;\frac{PV}{\gamma-1} & \quad (d)\;\frac{PV}{\gamma} \end {array}\]

1 Answer

$ (A)\;\frac{\gamma-1}{PV}$
Hence A is the correct answer.
answered Mar 24, 2014 by meena.p

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