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A transverse wave propagating on a stretched string of linear density $3 \times 10^{-4}\;kg-m^{-1}$ is represented by the equation $y=0.2 \sin (15 x +60 l)$ where x is in meters and l is in seconds . The tension in the string (in newton) is :

\[\begin {array} {1 1} (a)\;0.24 & \quad (b)\;0.48 \\ (c)\;1.20 & \quad (d)\;1.80 \end {array}\]
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1 Answer

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(B) 0.48
Hence B is the correct answer.
answered Mar 24, 2014 by meena.p

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