logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Vector Algebra

The number of distinct real values of $\lambda$ for which the vectors $-\lambda^2\hat i+\hat j+\hat k,\:\hat i-\lambda^2\hat j+\hat k\:and\:\hat i+\hat k-\lambda^2 \hat k$ are coplanar is?

$\begin{array}{1 1} 0 \\ 1 \\ 2 \\ 3 \end{array} $

1 Answer

For three vectors to be coplanar the condition is
$\left|\begin{array}{ccc} -\lambda^2 & 1 &1\\1 &-\lambda^2 & 1\\1 & 1& -\lambda^2\end {array}\right |=0$
Solving which $-\lambda^2(\lambda^4-1)-(-\lambda^2-1)+(1+\lambda^2)=0$
$\Rightarrow\:(\lambda^2+1)^2(2-\lambda^2)=0$
$\Rightarrow\:\lambda=\pm \sqrt 2$
$\therefore $ There are two real values of $\lambda$.
answered Nov 8, 2013 by rvidyagovindarajan_1
 

Related questions

Download clay6 mobile appDownload clay6 mobile app
...
X