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$\{ n(n+1)(2n+1): n \in Z \} \in $

\[\begin {array} {1 1} (a)\;\{6k:k \in Z\} & \quad (b)\;\{12k:k \in Z\} \\ (c)\;\{18k:k \in Z\}& \quad (d)\;\{24 k:k \in Z\} \end {array}\]

1 Answer

$ (a)\;\{6k:k \in Z\}$
answered Feb 27, 2014 by meena.p
 
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