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$\sum \limits _{n=1}^{\infty} \large\frac{2n^2+n+1}{n !}$ is equal to :

\[\begin {array} {1 1} (a)\;2e-1 & \quad (b)\;2e+1 \\ (c)\;6e-1 & \quad (d)\;6e+1 \end {array}\]
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1 Answer

(c) 6e-1
answered Feb 27, 2014 by meena.p
 
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