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The roots of the equation $x^3-3x-2=0$ are :

\[\begin {array} {1 1} (a)\;-1,-1,2 & \quad (b)\;-1,1,-2 \\ (c)\;-1,2,-3 & \quad (d)\;-1,-1,-2 \end {array}\]

1 Answer

(a) -1,-1,2
answered Feb 27, 2014 by meena.p
 
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