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If $ \large\frac{\tan 3A}{\tan A}$$=a$ then $\large\frac{\sin 3A}{\sin A}$ is equal to :

\[\begin {array} {1 1} (a)\;\frac{2a}{a+1} & \quad (b)\;\frac{2a}{a-1} \\ (c)\;\frac{a}{a+1} & \quad (d)\;\frac{a}{a-1} \end {array}\]

1 Answer

$(b)\;\frac{2a}{a-1}$
answered Feb 27, 2014 by meena.p
 
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