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Home  >>  EAMCET  >>  Mathematics
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If the vector $\overrightarrow{a} =2 \hat i+3 \hat j+6 \hat k$ and $\overrightarrow {b}$ are collinear and $|\overrightarrow {b}|=21,$ then $\overrightarrow {b}$ is equal to :

\[\begin {array} {1 1} (a)\;\pm(2 \hat i+3 \hat j+6 \hat k) & \quad (b)\;\pm3(2\hat i+3 \hat j+6 \hat k) \\ (c)\;( \hat i+ \hat j+ \hat k) & \quad (d)\;\pm 21(2 \hat i+3 \hat j+6 \hat k) \end {array}\]
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1 Answer

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$(b)\;\pm3(2\hat i+3 \hat j+6 \hat k)$
answered Feb 27, 2014 by meena.p
 

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