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Home  >>  EAMCET  >>  Mathematics
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If the range of a random variable X is $\{0,1,2,3,4.......\}$ with $P(X =k)= \large\frac{(k+1)a}{3^k}$ for $ k \leq 0,$ then a is equal to :

\[\begin {array} {1 1} (a)\;\frac{2}{3} & \quad (b)\;\frac{4}{9} \\ (c)\;\frac{8}{27} & \quad (d)\;\frac{16}{81} \end {array}\]

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1 Answer

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$ (b)\;\frac{4}{9}$
answered Feb 27, 2014 by meena.p
 
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