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For a binomial variate X with $n=6,$ if $P(X=2)=9\;P(X=4),$ then its variance is :

\[\begin {array} {1 1} (a)\;\frac{8}{9} & \quad (b)\;\frac{1}{4} \\ (c)\;\frac{9}{8} & \quad (d)\;4 \end {array}\]

1 Answer

$(c)\;\frac{9}{8}$
answered Feb 27, 2014 by meena.p
 
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