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The equation of the straight line perpendicular to $5x-2y=7$ and passing through the point of intersection of the lines $2x+3y=1$ and $3x+4y=6$ is :

\[\begin {array} {1 1} (a)\;2x+5y+17=0 & \quad (b)\;2x+5y-17=0 \\ (c)\;2x-5y+17=0 & \quad (d)\;2x-5y=17 \end {array}\]
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1 Answer

$(a)\;2x+5y+17=0$
answered Feb 27, 2014 by meena.p
 

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