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The area of the triangle formed by the pair of straight lines $(ax+by)^2-3(bx-ay)^2=0$ and $ax+by+c=0$, is :

\[\begin {array} {1 1} (a)\;\frac{c^2}{a^2+b^2} & \quad (b)\;\frac{c^2}{2(a^2+b^2)} \\ (c)\;\frac{c^2}{\sqrt 2 (a^2+b^2)} & \quad (d)\;\frac{c^3}{\sqrt 3 (a^2+b^2)} \end {array}\]

1 Answer

$ (d)\;\frac{c^3}{\sqrt 3 (a^2+b^2)} $
answered Feb 27, 2014 by meena.p
 
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