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Home  >>  EAMCET  >>  Mathematics
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The equation of the circle whose diameter is the common chord of the circles $x^2+y^2+2x+3y+2=0$ and $x^2+y^2+2x-3y-4=0$ is :

\[\begin {array} {1 1} (a)\;x^2+y^2+2x+2y+2=0 & \quad (b)\;x^2+y^2+2x+2y-1=0 \\ (c)\;x^2+y^2+2x+2y+1=0 & \quad (d)\;x^2+y^2+2x+2y+3=0 \end {array}\]
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1 Answer

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$ (c)\;x^2+y^2+2x+2y+1=0$
answered Feb 27, 2014 by meena.p
 
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