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If $R \to R$ is an even function which is twice differentiable on R and $f''(\pi)=1,$ then $f''(-\pi)$ is equal to :

\[\begin {array} {1 1} (a)\;-1 & \quad (b)\;0 \\ (c)\;1 & \quad (d)\;2 \end {array}\]

1 Answer

(c) 1
answered Feb 27, 2014 by meena.p
 

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