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A stone thrown upwards, has its equation of motion $s=490t-4.9t^2$. Then the maximum height reached by it , is:
\[\begin {array} {1 1} (a)\;24500 & \quad (b)\;12500 \\ (c)\;12250 & \quad (d)\;25400 \end {array}\]
jeemain
eamcet
math
2005
q67
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Nov 13, 2013
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meena.p
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(c) 12250
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Feb 27, 2014
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