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If $\int \sin ^{-1} \bigg( \large\frac{2x}{1+x^2}\bigg) $$dx-=f(x)-\log (1+x^2)+c$ then $f(x) $ is equal to :

\[\begin {array} {1 1} (a)\;2x \tan ^{-1} x & \quad (b)\;-2x \tan ^{-1} x \\ (c)\;x \tan ^{-1} x & \quad (d)\;-x \tan ^{-1} x \end {array}\]

1 Answer

$(a)\;2x \tan ^{-1} x $
answered Feb 27, 2014 by meena.p
 
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