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The area (in square units) bonded by the curves $y^2=4x$ and $x^2=4y$ in the plane is :

\[\begin {array} {1 1} (a)\;\frac{8}{3} & \quad (b)\;\frac{16}{3} \\ (c)\;\frac{32}{3} & \quad (d)\;\frac{64}{3} \end {array}\]

1 Answer

$(b)\;\frac{16}{3}$
answered Feb 27, 2014 by meena.p
 
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