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The position of a particle at time t is given by the equation $x(t) =\large\frac{v_0}{A}$$(1-e^{At})\; v_0=$ constant and $A > 0$ . Dimensions of $v_0$ and $A$ respectively are:
\[\begin {array} {1 1} (a)\;[MN^0LT^0]\;and\;[M^0L^0T^{-1}] & \quad (b)\;[M^0 LT{-1}]\;and\;[M^0LT^{-2}] \\ (c)\;[M^0LT^{-1}]\;and\;[M^0L^0T] & \quad (d)\;[M^0LT^{-1}] \;and\;[M^0L^0T^{-1}] \end {array}\]
jeemain
eamcet
physics
2004
q1
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asked
Nov 13, 2013
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meena.p
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