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The horizontal and vertical displacements x and y of a projectile at a given time t are given by $x=6t$ meter and $y=8 t -5t^2$ metre. The range of the projectile in meter is :

\[\begin {array} {1 1} (a)\;9.6 & \quad (b)\;10.6 \\ (c)\;19.2 & \quad (d)\;38.4 \end {array}\]

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1 Answer

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(A) 9.6
Hence A is the correct answer.
answered Mar 24, 2014 by meena.p

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