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Specify the unit of Equlibrium Constant of the following reaction.

$Fe^{3+} (aq) + SCN^- (aq) \rightleftharpoons Fe(SCN)^{2+} (aq)$

(a) $L mol^{-3}$

(b) $L mol^{-1}$

(c) $L$

(d) $mol^{-1}$

Can you answer this question?

$Fe^{3+} (aq) + SCN^- (aq) \rightleftharpoons Fe(SCN)^{2+} (aq)$
K = $\frac { [FeSCN^{2+} (aq)] } { [Fe^{3+} (aq)] [SCN^- (aq)] }$
Thus, Units = $\frac {(mol L^{-1})} {(mol L^{-1})(mol L^{-1})} = L mol ^{-1}$
answered Nov 13, 2013