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For the reaction $2A(g) + B(g) \rightleftharpoons 3C(g) + 4D(g)$ Three moles each of $A$ and $B$ were taken into a $1\; L$ flask. which of the following is always true when the system attains equilibrium?

(a) [A] = [B]

(b) [A] < [B]

(c) [B] = [C]

(d) [A] + [B] < [C] + [D]

From the equation, it is clear that 2 moles of A combine with one mole of B.

Let at equilibrium $a$ moles of B have reacted. This means that $2a$ moles of A have reacted.

$\therefore$ Equilibrium concentration of A = 2 - 2$a$
Equilibrium concentration of B = 2 - $a$

Hence [A] < [B]

edited Nov 23, 2013