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What are the units of Equilibrium equations $K_p$ and $K_c$ when $\Delta n_g < 0$ respectively ?

(a) $ (atm)^{\Delta n_g} , (L mol^{-1})^{\Delta n_g} $

(b) $ (atm)^{\Delta n_g} , (mol L^{-1})^{\Delta n_g} $

(c) $ (atm) , (L)^{\Delta n_g} $

(d) $ (atm) , (L mol^{-1})^{\Delta n_g} $

1 Answer

Toolbox:
  • $ K_p = K_c (RT)^{\Delta n_g} $
 
Answer: $(atm)^{\Delta n_g} $, $(L mol^{-1})^{\Delta n_g} $
 
According to the relationship between $ K_p $ and $ K_c $ when $ \Delta n_g < 0, $
 
Units of $K_p$ are $(atm)^{\Delta n_g} $.
 
Units of $K_c$ are $(L mol^{-1})^{\Delta n_g} $.

 

answered Nov 15, 2013 by mosymeow_1
edited Nov 23, 2013 by mosymeow_1
 

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