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In a $\Delta ABC$ if $b=2,B=30^{\large\circ}$ then the area of the circumcircle of $\Delta$ ABC in square unit is

$\begin{array}{1 1}(a)\;\pi&(b)\;2\pi\\(c)\;4\pi&(d)\;6\pi\end{array}$

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1 Answer

Given :
$b=2$
$B=30^{\large\circ}$
$R=\large\frac{b}{2\sin B}$
$\;\;=\large\frac{2}{\sin 30^{\large\circ}}$
$\;\;=\large\frac{2}{2\times\Large\frac{1}{2}}$
$\;\;=2$
Area =$\pi R^2$
$\qquad=\pi\times (2)^2$
$\qquad=4\pi$sq.unit
Hence (c) is the correct answer.
answered Nov 15, 2013 by sreemathi.v
 

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