Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

If $\sec\theta=m$ and $\tan\theta=n$ then $\large\frac{1}{m}$$\big[(m+n)+\large\frac{1}{(m+n)}\big]$

$\begin{array}{1 1}(a)\;2&(b)\;2m\\(c)\;2n&(d)\;mn\end{array}$

1 Answer

Comment
A)
Given that $\sec\theta=m$ and $\tan\theta=n$
$\therefore \large\frac{1}{m}$$\bigg[(m+n)+\large\frac{1}{m+n}\bigg]$
$\Rightarrow \large\frac{1}{\sec\theta}$$\big[\sec\theta+\tan\theta+\large\frac{1}{\sec\theta+\tan\theta}\big]$
$\Rightarrow \large\frac{1}{\sec\theta}$$\big[\sec\theta+\tan\theta+\sec\theta-\tan\theta]$
$\Rightarrow \large\frac{1}{\sec\theta}$$.2\sec\theta$
$\Rightarrow 2$
Hence (a) is the correct option.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...