Browse Questions

# We know that equilibrium constant, K changes with temperature. At 300K, equilibrium constant is 25 and at 400K it is 10. Hence, backward reaction will have energy of activation:

(a) equal to that of forward reaction

(b) less than that of forward reaction

(c) greater than that of forward reaction

(d) given values are not sufficient to explain given statement

• Van't Hoff equation: $log\frac{K_2}{K_1} = \frac{\Delta H}{2.303 \times R} [\frac{T_2 - T_1}{T_1 T_2}]$
• When $\Delta H = -ve$, then the reaction is exothermic