Browse Questions

# Volume of the flask in which species are transferred is double of the earlier flask. In which of the following reversible reactions, equilibrium will be shifted in the forward direction?

(a) $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$

(b) $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$

(c) $N_2(g) + O_2(g) \rightleftharpoons 2NO(g)$

(d) $2NO(g) \rightleftharpoons N_2(g) + O_2(g)$

Answer: $PCl_5 (g) \rightleftharpoons PCl_3 (g) + Cl_2 (g)$

As the volume is doubled, the pressure is reduced to one-half. Under these conditions, the equilibrium invloving increase in the number of moles of gaseous components in the forward direction will be shifted forward.

In $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$ reaction, there is a decrease in the number of moles of gaseous components in the forward direction.

$PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$ reaction, there is a increase in the number of moles of gaseous components in the forward direction.

$N_2(g) + O_2(g) \rightleftharpoons 2NO(g)$ reaction, the number of moles of gaseous components remains same in the forward direction.

$2NO(g) \rightleftharpoons N_2(g) + O_2(g)$ reaction, the number of moles of gaseous components remains same in the forward direction.

Thus, equation $PCl_5 (g) \rightleftharpoons PCl_3 (g) + Cl_2 (g)$ will be shifted in the forward direction.

edited Nov 23, 2013