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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Equilibrium
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$A + B \rightleftharpoons C + D$ One mole each of A and B and 3 moles each of C and D are placed in 1L flask, if equilibrium constant is 2.25. Equilibrium concentrations of A and C will be in the ratio:

(a) 2 : 3

(b) 3 : 2

(c) 1 : 2

(d) 2 : 1

Can you answer this question?
 
 

1 Answer

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Answer: 2 : 3
 
$ A + B \rightleftharpoons C + D $
1___1____3___3   at t=0 = Initial concentration
1-x_1-x__3+x__3+x   at t=t' At equilibrium
 
At equilibrium,
equilibrium constant $ K = \frac{[C][D]}{[A][B]} = \frac{(3+x)^2}{(1-x)^2} $
$ 2.25 = \frac{(3+x)^2}{(1-x)^2} $
$ \therefore \frac{3+x}{1-x} = 1.5 $
$ \Rightarrow 3+x = 1.5 - 1.5x $
$ \Rightarrow 2.5 x = -1.5$
$ \Rightarrow x = \frac{-15}{25} = \frac{-3}{5} $
 
Concentrations of A and C,
$ [A] = 1 - x = 1 + \frac{3}{5} = \frac{8}{5} $
$ [C] = 3 + x = 3 - \frac{3}{5} = \frac{12}{5} $
 
Ratio of concentration od A and C at equilibrium,
[A] : [C] = 8 : 12
or [A] : [C] = 2 : 3

 

answered Nov 16, 2013 by mosymeow_1
edited Nov 23, 2013 by mosymeow_1
 

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