Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

The kinetic energy energy K of a particle of mass 'm' moving along a circle of radius 'R' depends on distance covered 'S' as $K =AS^2$. Then the acceleration of particle is given by :

$\begin {array} {1 1} (1)\;\large\frac{2AS}{m} \bigg( 1+ \large\frac{S^2}{R^2} \bigg) ^{\large\frac{1}{2}} & \quad (2)\;\large\frac{2AS}{m} \bigg( 1- \large\frac{S^2}{R^2} \bigg) ^{\large\frac{1}{2}} \\ (3)\;\large\frac{2AS^2}{mR} & \quad (4)\;\large\frac{2AS^2}{m} \end {array}$


Can you answer this question?

1 Answer

0 votes
Ans : (1)
answered Feb 27, 2014 by thanvigandhi_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App