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The radius of gyration of a solid sphere of radius R about a certain axes is also equal to R. If r is the distance between the axes and the centre of a sphere , then r is equal to

$\begin {array} {1 1} (1)\;R & \quad (2)\;0.5 R \\ (3)\;\sqrt { 0.6}R & \quad (4)\;Zero \end {array}$


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Ans : (3)
answered Feb 27, 2014 by thanvigandhi_1
Give me the complete solution

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