Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

The period of revolution of Jupiter around the sun is 12 times the period of revolution of the earth around the sun. The distance between the Jupiter and sun is n times the distance between the earth and sun. Then the value of n is :

$\begin {array} {1 1} (1)\;(144)^{\large\frac{3}{2}} & \quad (2)\;(144)^{\large\frac{2}{3}} \\ (3)\;^3\sqrt{144} & \quad (4)\;^4\sqrt{144} \end {array}$


Can you answer this question?

1 Answer

0 votes
Ans : (3)
$ ^3\sqrt{144}$
answered Feb 27, 2014 by thanvigandhi_1
edited Mar 4, 2014 by thanvigandhi_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App