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The period of revolution of Jupiter around the sun is 12 times the period of revolution of the earth around the sun. The distance between the Jupiter and sun is n times the distance between the earth and sun. Then the value of n is :

$\begin {array} {1 1} (1)\;(144)^{\large\frac{3}{2}} & \quad (2)\;(144)^{\large\frac{2}{3}} \\ (3)\;^3\sqrt{144} & \quad (4)\;^4\sqrt{144} \end {array}$

 

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1 Answer

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Ans : (3)
$ ^3\sqrt{144}$
answered Feb 27, 2014 by thanvigandhi_1
edited Mar 4, 2014 by thanvigandhi_1
 

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