$\begin{array}{1 1}(a)\;100\pi sqcm&(b)\;5sqcm\\(c)\;25sqcm&(d)\;\large\frac{100\pi}{3}\normalsize sqcm\end{array}$

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In $\Delta$ABC $\angle A=30^{\large\circ}$

$BC=10$ cm

Let $O$ be the centre of the circle.

$\Rightarrow\:\angle BOC=60^{\large\circ}$

$OB$ and $OC\Rightarrow radius$

$\angle OBC=\angle OCB =60^{\large\circ}$

$\Rightarrow \Delta OBC$ is an equilateral $\Delta$le.

Radius of circle is $OB=OC=BC=10cm$

Area of the circumcircle is $\pi r^2$

$\Rightarrow \pi(10)^2$

$\Rightarrow 100\pi$sq.cm

Hence (a) is the correct answer.

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