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The surface of a metal has work function 2.66 e V. This is illuminated with photons of wavelength 450 nm. Te de Broglie wavelength of the emitted photoelectrons is : ( Mass of electron = $9 \times 10^{-31}$ kg)

$\begin {array} {1 1} (1)\;2.045 \times 10^{-9}m & \quad (2)\;4.09 \times 10^{-9}m \\ (3)\;8.18 \times 10^{-9}m & \quad (4)\;1.02 \times 10^{-9}m \end {array}$


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Ans : (2)
$4.09 \times 10^{-9}m$
answered Feb 27, 2014 by thanvigandhi_1

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