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If 200 MeV of energy is released in the fission of 1 nucleus of $_{92}U^{235}$, the number of nuclei that undergo fission to produce energy of 10 kwh in one second :

$\begin {array} {1 1} (1)\;11.25 \times 10^{18} & \quad (2)\;22.5 \times 10^{17} \\ (3)\;11.25 \times 10^{17} & \quad (4)\;22.5 \times 10^{18} \end {array}$

1 Answer

Ans : (3)
$ 11.25 \times 10^{17}$
answered Feb 27, 2014 by thanvigandhi_1
 

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