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The set of values of $\sec^{-1}\big(\frac{1}{2}\big)$ is ______________.

$\begin{array}{1 1} \frac{\pi}{6} \\ \frac{-\pi}{3} \\ \frac{\pi}{3} \\ \text{Not defined }\end{array} $

1 Answer

Toolbox:
  • Domain of sec\(^{-1}x\:is\:\:(-\infty,-1]\cup[1,\infty)\)
Ans:Not defined
 
\( sec^{-1}x\) is not defined for \( x \: \in\: (-1 \: 1) \)
\(\frac{1}{2}\notin\:the\:domain\: of\:sec^{-1}x\)
 
Therefore it is not defined

 

answered Feb 18, 2013 by thanvigandhi_1
edited Mar 16, 2013 by thanvigandhi_1
 
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