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# The set of values of $\sec^{-1}\big(\frac{1}{2}\big)$ is ______________.

$\begin{array}{1 1} \frac{\pi}{6} \\ \frac{-\pi}{3} \\ \frac{\pi}{3} \\ \text{Not defined }\end{array}$

Toolbox:
• Domain of sec$^{-1}x\:is\:\:(-\infty,-1]\cup[1,\infty)$
Ans:Not defined

$sec^{-1}x$ is not defined for $x \: \in\: (-1 \: 1)$
$\frac{1}{2}\notin\:the\:domain\: of\:sec^{-1}x$

Therefore it is not defined

edited Mar 16, 2013