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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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Find the 10th term of the AP -3, -1, 1, 3, ....

$(a)\;10\qquad(b)\;3\qquad(c)\;-3\qquad(d)\;15$

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  • In an Arithmetic progression (AP) , $ T_{n} = a + (n-1)d $
In an Arithmetic progression (AP), $ T_{n} = a + (n-1)d $
Here,  $a = -3, d = 2 $, we need to find the 10th term, $n = 10 $
$T_{10} = -3 + (10-1) 2 = -3 + 9 X 2 = -3 +18 = 15 $

 

answered Nov 19, 2013 by harini.tutor
 

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