(A) $\;\lambda=1$ (B) $\;\lambda=0$ (C) $\;\lambda=3$ (D) $\;\lambda=2$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

A non-homogenous system has unique solution if $D\neq 0$ and infinite solutions if $D=D_1=D_2=D_3=0$

Now $D=\begin{vmatrix}1 &1 &-2\\2 &-3&1\\1 &-5&4\end{vmatrix}$$=0$

Hence $D_1,D_2,D_3$ should all be zero.i.e $D_1=0$

$\Rightarrow D_1=\begin{vmatrix}0 &1&-2\\0 &-3&1\\\lambda &5&4\end{vmatrix}=0$

$\Rightarrow \lambda(1-6)=0$

$\lambda=0$

Hence (b) is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...