Want to ask us a question? Click here
Browse Questions
 Ad
0 votes

# The number of values of k for which the system of equations $(k+1)x+8y=4k,kx+(k+3)y=3k-1$ has infinitely many solutions is

(A) 0

(B) 1

(C) 2

(D) infinite

Can you answer this question?

## 1 Answer

0 votes
For infinitely many solutions the two equation become identical.
$\Rightarrow \large\frac{k+1}{k}=\frac{8}{k+3}=\frac{4k}{3k-1}$
$\Rightarrow k=1$
Hence (b) is the correct answer.
answered Nov 20, 2013

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer

0 votes
1 answer