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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Determinants

If $A=\begin{bmatrix}\alpha&2\\2&\alpha\end{bmatrix}$ and $\mid A^3\mid=125$ then the value of $\alpha$ is

$(a)\;\pm 1\qquad(b)\;\pm 2\qquad(c)\;\pm 3\qquad(d)\;\pm 5$

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1 Answer

$A=\begin{vmatrix}\alpha&2\\2 &\alpha\end{vmatrix}$
$\mid A^3\mid=125$
$\Rightarrow \mid A\mid=\alpha^2-4$
$\Rightarrow \mid A\mid^3=125$
$(\alpha^2-4)^3=125$
$(\alpha^2-4)^3=5^3$
$\alpha^2-4=5$
$\alpha^2=9$
$\alpha=\pm 3$
Hence (c) is the correct answer.
answered Nov 20, 2013 by sreemathi.v
 

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