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# Center of mass of two particles with masses 2 kg and 1 kg located at (1,0,1) and (2,2,0) has the coordinates of

$\begin {array} {1 1} (a)\;\frac{4}{3},\frac{2}{3},\frac{2}{3} \\ (b)\;\frac{2}{3},\frac{4}{3},\frac{2}{3} \\ (c)\;\frac{2}{3},\frac{2}{3},\frac{4}{3} \\ (d)\;\frac{1}{3},\frac{2}{3},\frac{2}{3} \end {array}$

$X_{cm}=\large\frac{m_1X_1+m_2X_2}{(m_1+m_2)}$
So the corret answer is $\large\frac{4}{3},\frac{2}{3},\frac{2}{3}$
edited Jun 16, 2014