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A uniform wire of length L is bent in the form of a circle. The shift in its centre of mass is

\[\begin {array} {1 1} (a)\;\frac{L}{\pi} \\ (b)\;\frac{2L}{\pi} \\ (c)\;\frac{L}{2 \pi} \\ (d)\;\frac{L}{3 \pi} \end {array}\]

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Shift 2 radius
$2 \pi R=L$
$R= \large\frac{L}{2 \pi}$
answered Nov 20, 2013 by meena.p
 

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