Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Determinants
Answer
Comment
Share
Q)

If $\begin{vmatrix}6i&-3i&1\\4&3i&-1\\20&3&i\end{vmatrix}=x+iy$ then

$\begin{array}{1 1}(a)\;x=3,y=1&(b)\;x=1,y=3\\(c)\;x=0,y=3&(d)\;x=0,y=0\end{array}$

1 Answer

Comment
A)
Given :
$\begin{vmatrix}6i &-3i&1\\4 &3i&-1\\20 &3 &i\end{vmatrix}=x+iy$
$\Rightarrow -3i\begin{vmatrix}6i &1&1\\4 &-1&-1\\20&i&i\end{vmatrix}$=0
$C_2$ and $C_3$ are identical.
$\Rightarrow x+iy=0$
$\Rightarrow x=0,y=0$
Hence (d) is the correct answer.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...