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The mass of a uniform ladder of Length 5 m is 20 kg. A person of mass 60 kg stands on the ladder at a height of 2 m from the bottom. The position of the center of mass of the ladder and man from the bottom is nearly

\[\begin {array} {1 1} (a)\;1\;m \\ (b)\;2.5\;m \\ (c)\;3.5\;m \\ (d)\;2.125\;m \end {array}\]

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$Ycm= \large\frac{60 \times 2 + 20 \times 2.5 }{80}$
$\qquad= 2.125\;m$
answered Nov 20, 2013 by meena.p
edited Jun 16, 2014 by lmohan717
 

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