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On a large tray of mass M an ice cube of mass m, edge L is kept. If the ice melts completely , the COM of the system comes down by

\[\begin {array} {1 1} (a)\;\frac{mL}{2(M+m)} \\ (b)\;\frac{(M-m)L}{2(M+m)} \\ (c)\;\frac{(M+2m)L}{2(M+m)} \\ (d)\;\frac{2ML}{(M+m)} \end {array}\]

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$d= \large\frac{m \times L}{2(m+M)}$
answered Nov 21, 2013 by meena.p

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