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A uniform circular sheet has a radius r. A square sheet whose diagonal length is equal to the radius of the plate is removed. The maximum distance of the centre of mass of the square sheet from the center of original sheet is :

\[\begin {array} {1 1} (a)\;\frac{r}{2(2 \pi-1)} & \quad (b)\;\frac{r}{(\pi-2)} \\ (c)\;\frac{2r}{\pi-3} & \quad  (d)\;\frac{r}{2(\pi-1)}\end {array}\]

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