Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Two particles of masses 1 kg and 3 kg have velocities $(2 \hat i-3 \hat j+4 \hat k)ms^{-1}$ and $(4 \hat {i}+2 \hat j+\hat k)ms^{-1}$ at a given instant of time. The velocity of the center of mass is

\[\begin {array} {1 1} (a)\;3.5 \hat{i}+2.25 \hat{j}+1.75 \hat {k} \;m/s\\ (b)\;3.5 \hat{i}-2.25 \hat{j}+1.75 \hat {k} \;m/s \\ (c)\;2.5 \hat{i}+2.25 \hat{j}+1.75 \hat {k} \;m/s \\(d)\;3.5 \hat{i}+0.75 \hat{j}+1.75 \hat {k} \;m/s  \end {array}\]

Can you answer this question?

1 Answer

0 votes
$\bar {V}cm=\large\frac{m_1\overrightarrow{v_1}+m_2 \overrightarrow {v_2}}{m_1+m_2}$
$\qquad= \large\frac{1(2 \hat {i}-3 \hat {j}+4 \hat {k})+3 (4 \hat {i}+2 \hat j+\hat {k})}{4}$
$\qquad= 3.5 \hat {i}+0.75 \hat i+1.75\hat k\;m/s$
answered Nov 21, 2013 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App